[Solved] Optimize runtime with index

How to optimize this SQL query?

In case you have your own slow SQL query, you can optimize it automatically here.

For the query above, the following recommendations will be helpful as part of the SQL tuning process.
You'll find 3 sections below:

  1. Description of the steps you can take to speed up the query.
  2. The optimal indexes for this query, which you can copy and create in your database.
  3. An automatically re-written query you can copy and execute in your database.
The optimization process and recommendations:
  1. Avoid Selecting Unnecessary Columns (query line: 2): Avoid selecting all columns with the '*' wildcard, unless you intend to use them all. Selecting redundant columns may result in unnecessary performance degradation.
  2. Create Optimal Indexes (modified query below): The recommended indexes are an integral part of this optimization effort and should be created before testing the execution duration of the optimized query.
  3. Prefer Direct Join Over Joined Subquery (query line: 4): We advise against using subqueries as they are not optimized well by the optimizer. Therefore, we recommend to replace subqueries with JOIN clauses.
  4. Use Numeric Column Types For Numeric Values (query line: 11): Referencing a numeric value (e.g. 72002506) as a string in a WHERE clause might result in poor performance. Possible impacts of storing numbers as varchars: more space will be used, you won't be able to perform arithmetic operations, the data won't be self-validated, aggregation functions like SUM won't work, the output may sort incorrectly and more. If the column is numeric, remove the quotes from the constant value, to make sure a numeric comparison is done.
Optimal indexes for this query:
CREATE INDEX zhr_jmk4_idx_id ON zhr_struct_jmk4 (id);
The optimized query:
        zhr_struct_jmk4 a 
            a.id >= 9000000 
            AND a.ID <= 100000000 
            AND a.SBEGD <= :iv_begda 
            AND a.sendd >= :iv_endda
        ) START WITH a.objid = '72002506' CONNECT 
        PRIOR a.id = a.sobid

Related Articles

* original question posted on StackOverflow here.